sqrt(10x + 6) = 9 - x 3) sqrt(3x ^ 2 - 4x - 4) = s - Dicamon

Question

sqrt(10x + 6) = 9 - x 3) sqrt(3x ^ 2 - 4x - 4) = sqrt(2x + 5) 5) sqrt(5 - 2x) + sqrt(3 - x) = 2; sqrt(2x ^ 2 - x - 20 - 2) = c 4 ) sqrt(- x ^ 2 + 7x - 6 + x = 4

Answer

) 110x x + 6 = 9 - x; 0k / 10 * x + 6 >= 0; 10x + 6 = (9 - x) ^ 2; 10x+6=9^ 2 -9.9.x+x^ 2 ) x ^ 2 - 28 + 75 = 0 ) 3 ) x = 25(M); (3x) = - 6/10; (-)x> -3 5 = ( ) 129x ^ 2 - x - 20 =

mng giúp mình từ câu 5 nhé(câu 8 bỏ nha)