C2 Cho beeii thic .R=(x+1/x-2 x+1+1/x-1)^x^2+x/x^2 - Dicamon

Question

C2 Cho beeii thic .R=(x+1/x-2 x+1+1/x-1)^x^2+x/x^2-1) (6) x+0, x ≠± 1 a) Rutan P b) Tive ques mi tai x=2/5 c) Tim sê rqueín x dé buî thée E rilânqua in nqurén

Answer

a)      P     =(x+1/x-2 x+1+1/x-1) ·x^2+x/x^2-1         =[x+1/(x-1)^2+1/x-1] ·x^2-1/x^2+x         =[(x+1)+(x-1)/(x-1)^2], (x+1)(x-1)/x(x+1)         =2 x/(x-1)^2·x-1/x=2/x-1

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