(1/3) ^ 7, (2/2) * x = [(2/3) ^ (2 - 2)] ^ 2 - Dicamon

Question

(1/3) ^ 7, (2/2) * x = [(2/3) ^ (2 - 2)] ^ 2

Answer

(1/3) ^ 2 + 2/7 * x = ((2/3) ^ 2) ^ 2; 1/(y ^ 7) + (2x)/t = (2 ^ 4)/(y ^ 4); (2x)/t = (2 ^ 4)/(y ^ 4) - 1/(y ^ 7) ( ) 2x 7 = 2^ 4 *3^ 2 -1 3^ 7 . 3077 4374 2.3

Answer

(1/3) ^ 7 + (2/7) * x = [(2/3) ^ 2] ^ 2; 1/2187 + (2/7) * x = (2/3) ^ 4; 1/2187 + (2/7) * x = 16/81; (2/7) * x = 431/2187 3017 4574

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