8 ) Cho 160 gam dd Iron ( III) sulfate Fe 2 (SO 4 - Dicamon

Question

8 ) Cho 160 gam dd Iron ( III) sulfate Fe 2 (SO 4 ) 3 0,5

Answer

1. nFe2(SO4)3=160×0,5 Fe2(SO4)3 + 3BaCI2 -> 2FeCI3 + 3BaSO4     0,005 —>    0,015                       0,015 a. mBaSO4=0,015×(137+32+16×4)=3,495g b. C 2. nH2SO4=1,2×0,125=0,15mol

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