A ^ 2 - B ^ 2 = (A - B) - (A + B); ((2x - 3) ^ 2)/ - Dicamon

Question

A ^ 2 - B ^ 2 = (A - B) - (A + B); ((2x - 3) ^ 2)/a - ((x - 1) ^ 2)/b = 0; (2x + 1) ^ 2 - (x - 1) ^ 2 = 0 ) (3x - 5) ^ 2 - (x + 1) ^ 2 = 0; (q + 2) ^ 2 - (2r -

Answer

(=)[x= 4 3; x = 2 . 1 ) (2x - 3) ^ 2 - (x - 1) ^ 2 = 0(3x - 4)(x - 2) = 0; (=)[ matrix 3x-4=0  x-2=0 matrix 2 ) (2x+1)^ 2 -(x-1)^ 2 =0(3x).(x+2)=0=2[ matrix x=0  x=0-2 3) (3x-5)^ 2

Answer

T ( 2x 3 2 ( x ) 0 ( 2x 3 x + 1 ) ( 2x 3 x ( 2x 1 x - ) ( 3x - = 2 3x 2 3x x = (alpha*x + 1) ^ 2 + (x - 1) * 2 = 0 2x + 1 + 1 ) ( 1 x 2 ) ( 3x 2 = 3x + 0 = 0 = 3x 0 =

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