(x + 3) ^ 2 - 2y ^ 3 = 6; 3 * (x + 2) ^ 2 + 5y ^ 3 - Dicamon

Question

(x + 3) ^ 2 - 2y ^ 3 = 6; 3 * (x + 2) ^ 2 + 5y ^ 3 = 7

Answer

+ ding r * cos(xf) / 2 = a(a * 70u(a + 3) * 7, 0); 1a ^ 1 - 2b = 6(- 1) - 3a + 6b = 86 - 18; 18a + 1b = 0; =111b=-1161 =-1=|a=2b+6 ) 4 x-1x=4(-12^ (x-3))^ 2 =2^ 2; 1b=-1^ prime

Answer

(x+3)^ 2 =2y^ 3 =62; -3(x+2)^ 2 +5y^ 3 =+; (3(n+2)^ 2 -6y^ 3 =18; 63 * (x + alpha) ^ 2 + 5y ^ 3 = 7 3 1 (x + 3) ^ 2 - 2y ^ 3 = 6 3 = - 4 * (1 + 3) ^ 2 = 6 + 2y ^ 3; y = - 1;

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